How many MS20470 AD-4-6 rivets are needed to attach a 10 x 5 inch plate using a single row with minimum edge distance and 4D spacing?

To determine the number of MS20470 AD-4-6 rivets required to attach a 10 x 5 inch plate using a single row with minimum edge distance and 4D spacing, it is essential to first understand the specifications of the rivet and the spacing requirements.

The MS20470 AD-4-6 rivet has a diameter of 1/8 inch. The "4D" spacing requirement means that the distance between each rivet center should be four times the diameter of the rivet. Therefore, the spacing between rivets will be:

4D = 4 * (1/8 inch) = 1/2 inch.

For a single row along the length of the 10-inch side of the plate, we start by calculating how many rivets can fit within the constraints of the plate length while considering the minimum edge distance. The minimum edge distance is typically about 1.5 times the diameter of the rivet, which ensures structural integrity. Using the diameter of 1/8 inch:

Minimum edge distance = 1.5 * (1/8 inch) = 3/16 inch.

When placing rivets, the first rivet can be placed at the edge plus the minimum